How to delete multiple elements from array in step by step process and how to store remaining elements in array

I have an array A=[1 0.2 7 0.5 3 8]

I want to delete lowest number from this array

A(A==0.2)=[]

A=[1 7 0.5 3 8]

now again I want to delet lowest number from this

A(A==0.5)=[]

A=[1 7 3 8]

Now, How do I store different lengths array for future reference.

array={[1 0.2 7 0.5 3 8];

[1 7 0.5 3 8];

[1 7 3 8];

[7 3 8];

[7 8];

[8]}

is it possible with while loop ???

Answer 1

[DGM]

For storing dissimilar size/type objects, you can use a cell array:

A = [1 0.2 7 0.5 3 8];

B = cell(numel(A),1);
B{1} = A;
for v = 2:numel(A)
	thisvec = B{v-1};
	[~,idx] = min(thisvec);
	thisvec(idx) = [];
	B{v} = thisvec;
end
B{:}

gives

ans =
    1.0000    0.2000    7.0000    0.5000    3.0000    8.0000
ans =
    1.0000    7.0000    0.5000    3.0000    8.0000
ans =
     1     7     3     8
ans =
     7     3     8
ans =
     7     8
ans =
     8

[BHUKYA VENKATESH]

Thanks!

can we do this using while loop??

[DGM]

You could use a while loop, but there's no good reason to use a while loop if the number of iterations is known. It's a lot harder to accidentally make a for-loop become infinite.

[BHUKYA VENKATESH]

thanks!

Answer 2

[Jan]

A = [1 0.2 7 0.5 3 8];
nA    = numel(A);
array = cell(nA, 1);
for k = 1:nA
   array{k} = maxk(A, nA - k + 1);
end

[BHUKYA VENKATESH]

Thanks!