finding maximum angle and managing data
    3 vues (au cours des 30 derniers jours)
  
       Afficher commentaires plus anciens
    
h=130;
H=50;
i=1;
x=30:0.5:300;
AC=sqrt(x.^2+(h+H)^2);
AB=sqrt(x.^2+(h)^2);
th=acos((AB.^2+AC.^2-H^2)./(2*AB.*AC));
[thMax n]=max(th);
xthMax=x(n);
fprintf('Distance is %6.3ft at Maximum angle %6.3 deg\n',xthMax,thMax)
Hi , I have done this so far but now I get this
Distance is 153.000t at Maximum angle Distance is 153.000t at Maximum angle 0.162 deg how can I take away the repetition of the Distance and the angle is not 0.162 deg it should be 9.282 according to my calculations , do you see anything wrong thanks for the feedback >>
0 commentaires
Réponse acceptée
  Matt J
      
      
 le 12 Juil 2013
        
      Modifié(e) : Matt J
      
      
 le 12 Juil 2013
  
      Use acosd() if you want the result in degrees instead of radians.
I don't see the repetition you mention when I run your code, but make sure that xthMax and thMax are scalars.
2 commentaires
  Matt J
      
      
 le 12 Juil 2013
				And your fprintf call should probably look like this
 fprintf('Distance is %6.3f at Maximum angle %6.3f deg\n',xthMax,thMax)
Plus de réponses (0)
Voir également
Catégories
				En savoir plus sur Numerical Integration and Differential Equations dans Help Center et File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!