Effacer les filtres
Effacer les filtres

FIR Filter 10th order with a for loop

4 vues (au cours des 30 derniers jours)
Abd Alsalam Al Saell
Abd Alsalam Al Saell le 2 Mai 2021
i'm trying to filter a signal with a 10th order differential equation and for loop, with the following code, but i'm keep getting this error
Array indices must be positive integers or logical values.
Error in EOG (line 106)
new_data = data_h(k:-1:k-10);
can you please help me fix it , and tell me if it's a code or just syntax error?
TimeStamp = 0:T:59.99;
N = 10;
Fg = 1;
Wn = Fg/2;
aTP = fir1(N,Wn);
for k = 1:numel(data_h)
new_data = data_h(k:-1:k-10);
Y(k) = aTP.*new_data;
end
plot(TimeStamp,data_h,TimeStamp,Y)
legend("data_h","Y")

Réponse acceptée

David Fletcher
David Fletcher le 2 Mai 2021
On the first iteration of your loop the indexing expression will expand to
new_data = data_h([1 0 -1 -2 -3 -4 -5 -6 -7 -8 -9])
As the error says: you can't index with zero or negative values
  2 commentaires
Abd Alsalam Al Saell
Abd Alsalam Al Saell le 3 Mai 2021
first of all thanks!
but one more error -_-
--> Unable to perform assignment because the indices on the left side are not compatible with the
size of the right side.
Error in EOG (line 108)
Y(k) = aTP.*new_data';
.
.
.
n = 0;
for k = 1:numel(data_h)
n = n+11;
new_data = data_h(k:n);
Y(k) = aTP.*new_data';
end
.
.
.
David Fletcher
David Fletcher le 3 Mai 2021
In this case the error is that you are trying to cram a vector into a single column. If you want to save the data from each iteration use:
Y(k,:) = aTP.*new_data';

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