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I need to plot the sum of 2 sine curves. I can successfully plot (x,y1) and plot(x,y2), they are smooth curves, however when i try to plot(x,y) where y = y1+y2 the curve comes out like this? how do i fix this i dont know what i am doing wrong? Thanks 

3 commentaires
"...however when i try to plot... the curve comes out like this"
You are plotting lots of zeros (to within floating point precision), because that is exactly what you calculated.
"how do i fix this i dont know what i am doing wrong?"
You need to consider the B factor. Note that for a B which is an integer multiple of 2*pi (and you defined B as 4*pi, which is clearly a multiple of 2*pi), the following identity holds true:
sin(B*X) = -sin(B*(1-X))
For example:
B = 2*pi;
X = rand(1,9);
sin(B*X)
sin(B*(1-X))
That is why you are plotting zeros (or at least values very very very close to zero).
Original question by Tyler Daines retrieved from Google Cache (unfortunately their deleted comments are not included):
Trying to plot a sine+sine function but not getting a smooth curve
I need to plot the sum of 2 sine curves. I can successfully plot (x,y1) and plot(x,y2), they are smooth curves, however when i try to plot(x,y) where y = y1+y2 the curve comes out like this? how do i fix this i dont know what i am doing wrong? Thanks

Rena Berman
le 29 Juin 2021
(Answers Dev) Restored edit
Réponses (2)
DGM
le 11 Mai 2021
What you're looking at isn't meaningful. It's all just rounding error. You're essentially doing this:
y = sin(x) - sin(x);
I'm guessing there's some phase component that's not defined right yet, but I can't really guess at what you need it to be.
f = 2;
A = 1;
v = 1;
L = 1;
l = v/f;
B = (2*pi)/l;
w = 2*pi*f;
t = 0;
x = 0:0.0001:L;
z1 = A*sin(B*x - w*t);
z2 = A*sin(B*(L-x) - w*t);
y = z1+z2;
plot(x,z2); hold on
plot(x,z1);

For the future, please just paste your code using the code formatting tools. I had to retype all that and deal with the sub-pixel ambiguity differentiating the character '1' and 'l'.
RAHUL MAURYA
le 12 Mai 2021
0 votes

clear all;
clc;
f = 2;
A = 1;
v = 1;
L = 1*(180/(pi));
l = v/f;
B = ((2*pi)/l)*(180/pi);
w = 2*pi*f;
t = 0;
x=0:0.0001:L;
z1 = (A*sind(B*x - w*t));
z2 = A*sind(B*(L-x) - w*t);
y=(z1+z2);
subplot(3,1,1);
plot(x,z1)
title('X,Z1')
axis([0 10 -1 1])
subplot(3,1,2);
plot(x,z2)
title('X,Z2')
axis([0 10 -1 1])
subplot(3,1,3);
plot(x,y)
title('X,Z1+Z2')
axis([0 10 -2 2])
Convert B and L in radian to degree.
1 commentaire
RAHUL MAURYA
le 12 Mai 2021
Convert B and L in degree from Radian
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