Using index to name variables

85 vues (au cours des 30 derniers jours)
Lukas Netzer
Lukas Netzer le 12 Mai 2021
Commenté : Lukas Netzer le 13 Mai 2021
I'm running a script with a index containing:
t{1} = Location1;
t{2} = Location2;
t{3} = Location3;
tt{1} = "Location1";
tt{2} = "Location2";
tt{3} = "Location3";
t's are tables. Now the actual script does e.g. this:
for x = 1:1:size(t{n})
if t{n}.var1(x) == 0
a_tt{n}(x) = b_tt{n}(x) / t{n}.var2(x);
if t{n}.var2(x) == 0
a_tt{n}(x) = 0;
end
As can be seen above I am trying to get a_Location1 and b_Location2 - but it does not work that way. Is there a smooth way to get a_location1/2/3 and b_location1/2/3 using the index?
It's for a lot of lines in the script, so some way without doing it by hand, would be nice!
Thanks for your help!
  2 commentaires
Lukas Netzer
Lukas Netzer le 12 Mai 2021
one solution that would work is:
str1 = "a_" + tt{n};
str2 = "b_" + tt{n};
But as stated above, I have lots of those variables, is there maybe a better way?
Rik
Rik le 12 Mai 2021
Why do you want numbered variables? You shouldn't store data in a variable name.

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Réponse acceptée

Jan
Jan le 12 Mai 2021
Do not create variables names dynamically. This would store information in the names, where it is hard to access. Use the values of the variables instead.
You can use dynamic field names of structs:
a = struct()
for x = 1:1:size(t{n})
if t{n}.var1(x) == 0
a.(tt{n})(x) = b_tt{n}(x) / t{n}.var2(x);
elseif t{n}.var2(x) == 0
a.(tt{n})(x) = 0;
end
end
  1 commentaire
Lukas Netzer
Lukas Netzer le 13 Mai 2021
Thank you very much - still alot to learn!

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