how to convert decimal values into 8bit binary sequence

hello everyone,

I am trying to convert 14*3 matrix integer value to 8bit binary sequence in a same matrix dimension.

i am using dec2bin function to achieve that but the result is not the same i expected.

A=[8	7	1;
4	10	1;
9	7	1;
7	10	1;
9	6	1;
4	8	1;
10	10	1;
2	7	255;
8	3	255;
7	5	255;
4	4	255;
4	6	255;
1	3	255;
2	5	255];

b=dec2bin(A,8);

please help me with this.It will be really helpful.

Thanks in adavance.

Answer 1

[VBBV]

%if true
for i = 1:length(A); 
iwant{:,i} = dec2bin(A(i,:));
end

This results in a 1x14 cell array converted to binary characters

[Chandrashekar D S]

Its kinda helped thanks