summing up array element

Hello,
I am new to programming, I have an array like p = [3 6 2 5];
I need c = [3 9 11 16]; First element in the array is as it is, when it goes to next element it has to sum the previous element.
Regards, SBN

Réponses (4)

Cedric
Cedric le 25 Juil 2013
Modifié(e) : Cedric le 25 Juil 2013

2 votes

Hi, use CUMSUM:
>> p_csum = cumsum(p)
p_csum =
3 9 11 16

2 commentaires

Bathrinath
Bathrinath le 25 Juil 2013
Thanks it works. Can you give the solution in for loop .
Cedric
Cedric le 25 Juil 2013
Modifié(e) : Cedric le 25 Juil 2013
Did you try building a solution based on a FOR loop? What did you implement so far?

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Evan
Evan le 25 Juil 2013
Modifié(e) : Evan le 25 Juil 2013

1 vote

help cumsum
>> s = cumsum(p)
s =
3 9 11 16

1 commentaire

Bathrinath
Bathrinath le 25 Juil 2013
Thanks it works. Can you give the solution in for loop .

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Andrew Reibold
Andrew Reibold le 25 Juil 2013
Modifié(e) : Andrew Reibold le 25 Juil 2013

1 vote

Here is your solution in a really easy loop.
p = [3 6 2 5]; %Can have as many numbers as you want
for n = 2:length(p) %n can be whatever counter you want.
p(n) = p(n)+p(n-1); %semi-colon suppresses output
end
-Andrew
Iain
Iain le 25 Juil 2013
Modifié(e) : Iain le 25 Juil 2013

0 votes

for i = 1:numel(p)
c(i) = sum(p(1:i));
end
Or
so_far = 0;
for i = 1:numel(p)
so_far = so_far + p(i);
c(i) = so_far;
end
or
for i = 1:numel(p)
s = 0;
for j = 1:i
s = s+ p(j);
end
c(i) = s;
end

1 commentaire

Jan
Jan le 25 Juil 2013
These are inefficient solutions, because the complete sum is calculated in each iteration. While this might not matter for 4 elements, the runtime will grow rapidly for longer data.
It is more efficient to re-use the sum for the elements 1 to i, when the sum until the i+1.th element is obtained. See Andrews answer.

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le 25 Juil 2013

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le 11 Sep 2021

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