How do i create a large matrix with a formula?

2 vues (au cours des 30 derniers jours)
Kane OConnor
Kane OConnor le 17 Mai 2021
Modifié(e) : James Tursa le 17 Mai 2021
I want to create a matrix with the pattern below for N = 1000, i.e a 1000 X 2 matrix?

Réponses (2)

James Tursa
James Tursa le 17 Mai 2021
Modifié(e) : James Tursa le 17 Mai 2021
N = 1000;
a = 2 * pi * f * T * (0:N-1)';
x = [cos(a) -sin(a)];

Paul Hoffrichter
Paul Hoffrichter le 17 Mai 2021
Modifié(e) : Paul Hoffrichter le 17 Mai 2021
Since you did not specify T and f, I assume you wanted symbolic notation. (I picked N = 10 to show a brief output.)
N=10;
n = 0:N-1;
syms T f
vec1 = cos(2*pi*f*n/T).';
vec2 = -sin(2*pi*f*n/T).';
X = [vec1 vec2]
Output (on R2020a):
X =
[ 1, 0]
[ cos((2*pi*f)/T), -sin((2*pi*f)/T)]
[ cos((4*pi*f)/T), -sin((4*pi*f)/T)]
[ cos((6*pi*f)/T), -sin((6*pi*f)/T)]
[ cos((8*pi*f)/T), -sin((8*pi*f)/T)]
[ cos((10*pi*f)/T), -sin((10*pi*f)/T)]
[ cos((12*pi*f)/T), -sin((12*pi*f)/T)]
[ cos((14*pi*f)/T), -sin((14*pi*f)/T)]
[ cos((16*pi*f)/T), -sin((16*pi*f)/T)]
[ cos((18*pi*f)/T), -sin((18*pi*f)/T)]

Catégories

En savoir plus sur Fourier Analysis and Filtering dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by