How to change seconds since 1st January 1985 to YYYY-MM-DD-HR-M-S format?
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I am a new user of MATLAB and was hoping to get some help to what is probably a very basic question to most of you. I am using data that currently represents time in seconds since 1st January 1985 and have been trying to change this to a format of YYYY-MM-DD-HR-M-S, however my attempts have been completely unsuccessful thus far. The data I am using ranges from 2003-2008. This is as much as I have come up with so far.
> t=86400; %86400 seconds in a day
> datestr(t/86400+datenum(1985,1,1))
Any help or guidance would be really appreciated. Cheers
1 commentaire
Jan
le 29 Juil 2013
What do you get as result of your code and what do you expect? I'd suggest exactly the same way, because it is the most efficient one.
Réponses (2)
Azzi Abdelmalek
le 29 Juil 2013
Modifié(e) : Azzi Abdelmalek
le 29 Juil 2013
dat0='01-01-1985 00:00:00'
dat00=datevec(dat0,'dd-mm-yyyy HH:MM:SS')
a=95604
dat00(6)=dat00(6)+a
new_de=datestr(datenum(dat00))
1 commentaire
Jan
le 29 Juil 2013
Your dat00 contains the same information as David's datenum(1985,1,1). Adding the number of seconds to the 6.th component of the date vector is the same as adding t/86400 to the datenumber. Therefore I do not see the difference to the original approach.
Iain
le 29 Juil 2013
seconds_since_1985 = 981364894; %
days_since_1985 = seconds_since_1985 / 86400;
datestr(days_since_1985 + datenum('1/1/1985'), 'YYYY-MM-DD-hh-mm-ss')
1 commentaire
Jan
le 29 Juil 2013
This looks also identical to the original version.
"MM" means minutes, while "mm" means months. So you have to swap upper- and lower-case.
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