Sort fields of struct by length and alphabetically

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Michel C
Michel C le 20 Mai 2021
Commenté : KAE le 20 Août 2021
I've been trying to sort the fields of a struct by combination of length and name. Length should take precedence, but if the length of two or more fields is equal (for example if they are scalar), those should be sorted alphabetically (within that group), where names starting with capital letter should take precedence. I'm coming up with nothing that works. Anybody?
Best regards MC
  1 commentaire
KAE
KAE le 20 Août 2021
The built in function orderfields might help.

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Stephen23
Stephen23 le 20 Mai 2021
Modifié(e) : Stephen23 le 20 Mai 2021
S.aa = rand(3,1);
S.bb = 1;
S.cc = rand(8,2);
S.dd = 1;
S.Ee = 1;
S.Ff = rand(3,1)
S = struct with fields:
aa: [3×1 double] bb: 1 cc: [8×2 double] dd: 1 Ee: 1 Ff: [3×1 double]
Method one: sort and indexing:
N = structfun(@numel,S);
F = fieldnames(S);
[~,X] = sort(F);
[~,Y] = sort(N(X),'descend');
Z = orderfields(S,F(X(Y)))
Z = struct with fields:
cc: [8×2 double] Ff: [3×1 double] aa: [3×1 double] Ee: 1 bb: 1 dd: 1
Method two: table and sortrows:
[~,X] = sortrows(table(N,F),[-1,2]);
Z = orderfields(S,F(X))
Z = struct with fields:
cc: [8×2 double] Ff: [3×1 double] aa: [3×1 double] Ee: 1 bb: 1 dd: 1

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