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how to solve this nonlinear equation?

2 vues (au cours des 30 derniers jours)
Pritha
Pritha le 21 Mai 2021
Modifié(e) : Torsten le 22 Mai 2021
m = 4.7542;
gsms = 12.684 ;
m1 = (m - gss);
p = 0.1 : 0.5 : 10 ;
k = (3 * p * pi^2 / 2)^(1/3) ;
k1 = sqrt(k^2 + m1^2);
F = (gsms * m1 * (k1 - m1^2/2 *log((k1+k)/m1))/pi^2 )-gss ;
  2 commentaires
Tayyab Khalil
Tayyab Khalil le 21 Mai 2021
Can you clearly desribe which equation you want to solve and for which variable?
Dyuman Joshi
Dyuman Joshi le 21 Mai 2021
What is gss?
Also, you have defined k and k1 incorrectly, use elementwise operators (.*)

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Torsten
Torsten le 21 Mai 2021
Modifié(e) : Torsten le 22 Mai 2021
function main
p=0.1:0.5:10;
gss0 = 1.0;
for i=1:numel(p)
gss(i)= fzero(@(x)fun(x,p(i)),gss0)
gss0 = gss(i);
end
plot(p,gss)
end
function gssres = fun(gss,p)
m = 4.7542;
gsms = 12.684;
m1 = m - gss;
k = (3*p*pi^2 / 2)^(1/3);
k1 = sqrt(k^2+m1^2);
F = gsms*m1*( k1-m1^2/2*log((k1+k)/m1) )/pi^2 - gss
gssres = F ;
end
Maybe you will have to change gss0 = 1.0 (a guess for gss for p=0.1) to make the program start.

Plus de réponses (1)

Mike Mierlo van
Mike Mierlo van le 21 Mai 2021
Please specify variable: 'gss'. This one is unknown in your function.
Also what Tayyab says: what do you want to solve?
It helps a lot if you comment with % after each line what the variable means.

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