unexpected use of 00:00:01 in a scalar context matlab

4 vues (au cours des 30 derniers jours)
Andrea Sbaragli
Andrea Sbaragli le 24 Mai 2021
Commenté : Andrea Sbaragli le 24 Mai 2021
if abs(Int12{i,6}- F1{j,1}) <= '00:00:01' why is it not corret?
  1 commentaire
Daniel Pollard
Daniel Pollard le 24 Mai 2021
Can you give some more context? Since we don't know what Int12 or F1 are, it's not easy to help. What are you trying to do?

Connectez-vous pour commenter.

Réponse acceptée

Walter Roberson
Walter Roberson le 24 Mai 2021
In MATLAB '00:00:01' is a character vector. When you use a character vector in a numeric expression, most of the time the character vector will have each character converted to the Unicode position number used to encode the character.
double('00:00:01')
ans = 1×8
48 48 58 48 48 58 48 49
You would then be comparing whatever is on the left side of the < to that vector of numbers, getting out a vector of logical results.
If the values you are working with just happen to be datetime objects then subtracting would give a duration object. You can then compare
if abs(Int12{i,6}- F1{j,1}) <= duration('00:00:01')
or more compactly
if abs(Int12{i,6}- F1{j,1}) <= seconds(1)

Plus de réponses (0)

Catégories

En savoir plus sur Dates and Time dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by