How can I find indices?

I have two matrices:

A=[1 2 3 3 1 1 2 1;
   1 1 1 2 2 3 2 3];
B=[2 1;
   1 3];

The output matrix will be either

indx=[2, 6];

or

indx=[0 1 0 0 0 1 0 0];

Is there any smart way? I can definately solve it by using loop and conditional statement.

Appreciated!

[KSSV]

What is output matrix?

[SM]

indx=[2, 6]; or indx=[0 1 0 0 0 1 0 0];

If you look at A and B, B(:,1) matches with A(:,2), and B(:,2) matches with A(:,6) and A(:,8). I need only one index of an column array. Thus, output should be indx=[2, 6].

Answer 1

[Stephen23]

A = [1,2,3,3,1,1,2,1;1,1,1,2,2,3,2,3]

A = 2×8

1 2 3 3 1 1 2 1 1 1 1 2 2 3 2 3

B = [2,1;1,3]

B = 2×2

2 1 1 3

[~,X] = ismember(B.',A.','rows')

X = 2×1

2 6

Answer 2

[Image Analyst]

Explain to me how you got [2,6] because it's not obvious to me. Your tag says "matches" and to find B in A, you can do this:

A=[1 2 3 3 1 1 2 1;
   1 1 1 2 2 3 2 3];
B=[2 1;
   1 3];
[rowsA, colsA] = size(A);
[rowsB, colsB] = size(B);
counter = 1;
index = [];
for col = 1 : (colsA - colsB + 1)
	subA = A(:, col : col + colsB - 1)
	if isequal(subA, B)
		index(counter) = k;
	end
end
index

but you can see your B never appears anywhere in your A. Are you perhaps just looking at the top row of each? But even that will not work because [2,1] occurs only at column 7-8.