Creating a Matrix with a pattern

I am trying to create a pattern that starts to follow a pattern starting at the second row in the first column, then on the third row but starts on the second column and continues until an n term, creating a [n;n] matrix. The pattern is similar to this matrix:

A = [ 2,-2,0,0,0,0,0,0,0,0,0; -2,4,-2,0,0,0,0,0,0,0,0; 0,-2,4,-2,0,0,0,0,0,0,0; 0,0,-2,4,-2,0,0,0,0,0,0;

0,0,0,-2,4,-2,0,0,0,0,0; 0,0,0,0,-2,4,-2,0,0,0,0; 0,0,0,0,0,-2,4,-2,0,0,0; 0,0,0,0,0,0,-2,4,-2,0,0;

0,0,0,0,0,0,0,-2,4,-2,0; 0,0,0,0,0,0,0,0,-2,4,-2; 0,0,0,0,0,0,0,0,0,-2,4]

I am wondering how I can replicate the pattern above in a similar code then typing it out.

[Walter Roberson]

A = [ 2,-2,0,0,0,0,0,0,0,0,0; -2,4,-2,0,0,0,0,0,0,0,0; 0,-2,4,-2,0,0,0,0,0,0,0; 0,0,-2,4,-2,0,0,0,0,0,0;
    0,0,0,-2,4,-2,0,0,0,0,0; 0,0,0,0,-2,4,-2,0,0,0,0; 0,0,0,0,0,-2,4,-2,0,0,0; 0,0,0,0,0,0,-2,4,-2,0,0;
    0,0,0,0,0,0,0,-2,4,-2,0; 0,0,0,0,0,0,0,0,-2,4,-2; 0,0,0,0,0,0,0,0,0,-2,4]

A = 11×11

2 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2

Answer 1

[Walter Roberson]

N = 11;
diag([2, 4*ones(1,N-2), 2]) + diag(-2*ones(1,N-1),1) + diag(-2*ones(1,N-1),-1)

ans = 11×11

2 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2