My stochastic processes program

4 vues (au cours des 30 derniers jours)
reem
reem le 30 Mai 2011
Hello My teacher Matt
I have a program and When I asked my teacher if my solution is
true or not,he said to me that my solution is not correct
Please,could you help me
My program
N=400; %Define Number of samples((times))
f1=1; % Frequency of the cosinewave
FS=200; % Sampling Frequency
Q=0;
t=1:400;
n=0:N-1;
X1=0;
for i=1:400
for j=1:301
X=cos((2*pi*f1*(n/FS))+Q);
X1=X1+X;
Q= -2*pi/N;
end
Q=Q*2;
end
subplot(2,1,1); % Prepare the figure
plot(t,X1/(400*301)) % Plot mean value vs. t
grid;
title('mean value function of cosinewave ');
xlabel('Time index');
ylabel('Mean value');
Rxx=xcorr(X1); % Estimate its autocorrelation
subplot(2,1,2);
plot(Rxx); % Plot the autocorrelation
grid;
title('Autocorrelation function of the cosinewave');
xlabel('Time index');
ylabel('Autocorrelation');
My teacher at university said to me that I have mistake here and
he wrote this note but I did not understand what he mean!!!
X=cos((2*pi*f1*(n/FS))+Q); % Generate x(t)
Here X must be as X(i,j). Then it has 400 rows and 301 columns. Row number equals to the number of realizations
  1 commentaire
Oleg Komarov
Oleg Komarov le 30 Mai 2011
Can you please format the code properly: http://www.mathworks.com/matlabcentral/answers/7885-tutorial-how-to-format-your-question

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Réponses (1)

Oleg Komarov
Oleg Komarov le 30 Mai 2011
You basically calculate the same X all the time. Nothing changes inside the loops.
  4 commentaires
reem
reem le 30 Mai 2011
Yes,you are true
so I must apply that,isn't it???
Q1=Q1+Q
Oleg Komarov
Oleg Komarov le 30 Mai 2011
Maybe, I don't know what is the stochastic process you have to reproduce.
Also, you probably have to change one of the input of X according to the indices i and j but the only vector you have in the expression is n (1 by 400) so you can use n(i), but this leaves the j index unused.

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