contour map for stress distribution
17 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I want to plot a contour map. It relates to stress distribution of a circular area. My trial as follows:
X =linspace(-4.5,4.5);
R=linspace(-4.5,4.5) ;
[X,Y] = meshgrid(X,Y);
Z= 3426.8/63.3+660*X*4/3.14/4.5^4+1700*sqrt(R^2-X^2)*4/3.14/4.5^4;
contourf(X,Y,Z)
Q1) How can i obtain continuous contour and its scale
0 commentaires
Réponses (2)
Sulaymon Eshkabilov
le 31 Mai 2021
HI,
Here is a corrected code:
X =linspace(-4.5,4.5);
R=linspace(-4.5,4.5) ;
[X,Y] = meshgrid(X,R);
Z= 3426.8/63.3+660*X*4/3.14/4.5^4+1700*sqrt(Y.^2-X.^2)*4/3.14/4.5^4;
contour3(X,Y,abs(Z))
0 commentaires
DGM
le 31 Mai 2021
Modifié(e) : DGM
le 31 Mai 2021
I don't know what you're doing, but this at least runs:
X = linspace(-4.5,4.5);
R = linspace(-4.5,4.5);
[X,Y] = meshgrid(X,R);
Z = 3426.8/63.3 + 660*X*4/3.14/4.5^4 + 1700*sqrt(Y.^2-X.^2)*4/3.14/4.5^4;
numlevels = 20; % set to whatever you want
contourf(X,Y,abs(Z),numlevels,'edgecolor','none')
I doubt that's what you want, but it's what I could guess from what you wrote. If you figure out what you're trying to plot, you can use contourf() with however many levels you want to get more Z-resolution. At some point though, it stops being useful as a contour map. Otherwise, you can just display Z using imagesc().
EDIT:
I decided to adopt Sulaymon's interpretation of intent. That makes a bit more sense.
2 commentaires
DGM
le 31 Mai 2021
That still doesn't make sense. You have a plot that's R on one axis and X on the other. As far as your coordinate setup indicates, you have a sectional plot. Like I said. I doubt it's what you want, but it's what you wrote. I don't know how you want to make this into something else.
If you can represent your information in polar coordinates, you could do something like this:
Voir également
Catégories
En savoir plus sur Contour Plots dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!