How do I put it in?

x1 = [-4.2 -2.6 -1 0.6 2.2 3.8 5.4 7 8.6]
x2 = [0.8 2.4 4 5.6 7.2 8.8 10.4 12 13.6]
predictor([x1 x2], dmodel)

[-4.2 0.8], [-4.2 2.4],[-4.2 4],[-4.2 5.6],[-4.2 7.2],[-4.2 8.8],[-4.2 10.4],[-4.2 12],[-4.2 13.6]

[-2.6 0.8],[-2.6 2.4],[-2.6 4],[-2.6 5.6] , ...

I want to put all the x2 values in one x1 value sequentially.

Please let me know! Thank you!

Answer 1

[DGM]

This isn't quite what you describe, since you're describing a series of 1x2 vectors, but:

x1 = [-4.2 -2.6 -1 0.6 2.2 3.8 5.4 7 8.6];
x2 = [0.8 2.4 4 5.6 7.2 8.8 10.4 12 13.6];

N = numel(x1);
[repelem(x1,N).' repmat(x2.',[N 1])]

ans = 81×2

-4.2000 0.8000 -4.2000 2.4000 -4.2000 4.0000 -4.2000 5.6000 -4.2000 7.2000 -4.2000 8.8000 -4.2000 10.4000 -4.2000 12.0000 -4.2000 13.6000 -2.6000 0.8000

[Star Strider]

There is actually a simpler way to do this:

x1 = [-4.2 -2.6 -1 0.6 2.2 3.8 5.4 7 8.6];
x2 = [0.8 2.4 4 5.6 7.2 8.8 10.4 12 13.6];

[X1,X2] = meshgrid(x1,x2);
Result = [X1(:) X2(:)]

Result = 81×2

-4.2000 0.8000 -4.2000 2.4000 -4.2000 4.0000 -4.2000 5.6000 -4.2000 7.2000 -4.2000 8.8000 -4.2000 10.4000 -4.2000 12.0000 -4.2000 13.6000 -2.6000 0.8000

.

[민제 강]

Thank you!

I have one more question.

How do I apply it to this function in the same way?

function Y = objectivefunction (X)

x1
x2

a = 1;
b = 5.1/(4*pi^2);
c = 5/pi;
r = 6;
s = 10;
t = 1/(8*pi);

Y = a*(x2 - b*x1^2 + c*x1 - r)^2 + s*(1-t)*cos(x1) + s

end

[DGM]

I have no idea about the requirements of whatever predictor thing you're working with. More generally if you just want to pass two arguments to some function but the calling function only allows you to pass one, you could probably just concatenate the vectors as dimensions allow and then split them afterwards, or you could just stick them in a cell array. I don't see that including every combination is required as in my answer (or SS's).

Maybe someone can chime in with a more specific way to do what you're trying to do for the calling function you're using. I don't do anything with machine learning tools, so maybe suggesting a cell array is a bad idea on my part.

Answer 2

[Sulaymon Eshkabilov]

It is quite simple.

x1 = [-4.2 -2.6 -1 0.6 2.2 3.8 5.4 7 8.6];
x2 = [0.8 2.4 4 5.6 7.2 8.8 10.4 12 13.6];
x1 = [x1, x2];