# Build an array of square and square root of user input

4 vues (au cours des 30 derniers jours)
Mina le 4 Juin 2021
The aim of this project is to build an array depending on a number from 1 to 10 entered by the user.
From 1 to num, all multiples of 2 should be squared and for all other numbers, the element should be square rooted.
Build the array sqr as the square or square-root (see story above) of all the numbers from 1 to the number entered by the user.
Display the array you built.
##### 4 commentairesAfficher 2 commentaires plus anciensMasquer 2 commentaires plus anciens
Bob Thompson le 4 Juin 2021
What is the specific problem you're having with the code? This seemed to work for me.
Mina le 4 Juin 2021
I'm not sure how to display the outputs as an array

Connectez-vous pour commenter.

### Réponse acceptée

David Fletcher le 4 Juin 2021
Modifié(e) : David Fletcher le 4 Juin 2021
The code you have written largely does what is asked, the only thing that is missing is that you are throwing the calculated sqr value away on each iteration of the loop rather than building an array from the values. You just need to save the values into the sqr vector by using the loop iterator to index into the vector. I suppose if you are being pedantic, the question asks you to display the array that has been built wheras you are displaying each value separately as it is calculated, but I think you've demonstated you can easily remedy that yourself.
clear
num = input('Please enter your favourite number between 1 and 10: ');
while num < 1 || num > 10
num = input('Invalid input. Please enter your favourite number between 1 and 10: ');
end
sqr = 1:num;
for i = 1:num
if mod(i,2) == 0
sqr(i) = i.^2;
else
sqr(i) = sqrt(i);
end
fprintf ('%6.4f \n', sqr(i));
end
disp(sqr);
##### 0 commentairesAfficher -2 commentaires plus anciensMasquer -2 commentaires plus anciens

Connectez-vous pour commenter.

### Catégories

En savoir plus sur Linear Programming and Mixed-Integer Linear Programming dans Help Center et File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by