please help me to convert c code into matlab code for partial shading of solar panel using equilibration algorithm

hei please convert this c code into matlab code

#include<stdio.h>

void main(){

float p1,p2,p3;

float delta=1;

scanf("%f%f%f",&p1,&p2,&p3);

float d = p2;

if(p1 != p2)

{

if(p1>p2)

{

if(p2>p3)

{

d=d-delta;

delta=delta*2;

}

else if(p2=p3)

{

d=d-delta;

delta=delta*2;

}

else

{

delta=delta/2;

}

}

else

{

if(p3>p2)

{

d=d+delta;

delta=delta*2;

}

else if(p2=p3)

{

d=d+delta;

delta=delta*2;

}

else

{

delta=delta/2;

}

}

}

else if(p1==p2)

{

if(p2>p3)

{

if(p2>p3)

{

d=d-delta;

delta=delta/2;

}

else if(p2<p3)

{

d=d-delta;

delta=delta*2;

}

else

{

delta=delta*2;

}

}

}

}

Answer 1

[Image Analyst]

You can do it.

1. Replace } (closing braces) with end.
2. Get rid of { (opening braces).
3. Replace != with ~=.
4. Get rid of float.
5. Replace "else if" with "elseif" (no space)

Not sure what's going on here:

scanf("%f%f%f",&p1,&p2,&p3);

Come on, it's not beyond your capabilities. Give it a try. This is how you learn.

[James Tursa]

The scanf(etc) is just inputting numbers p1, p2, p3.

Answer 2

[James Tursa]

In addition to what @Image Analyst has written, I would advise turning this into a function with p1, p2, p3 as input arguments and d, delta as output arguments.

Also, the C code appears to have bugs. These lines:

else if(p2=p3)

should from context probably be this instead:

else if(p2==p3)

The p2=p3 expression is an assignment in C that is then tested for non-zero, not an equality test, so this expression will be true whenever p3 is non-zero. You should double check your algorithm to confirm this is a bug. The MATLAB code for an equality test should use the == operator also.