Problem with Empty matrix: 1-by-0

My variables and their values, in the 'If' condition statement

leftoverROI1s{1}= [11 15];

missinglabelsinimage{1} is an empty matrix.

I want to execute a 'for' loop only if both my conditions in the 'if' statement are true, i.e.,: if((~isempty(leftoverROI1s{1})) && (~isempty(missinglabelsinimage{1})))

for % loop for each element in non-empty missinglabelsinimage structure array. Add a scalar to each element of non-empty missinglabelsinimage structure array

end % end for loop

end % end if

My program control is going into for loop (which I expect, it shouldn't if there is an empty missinglabelsinimage{1}) and the control is working on 'missinglabelsinimage{1}' (empty matrix), which obviously gives me an error as I am trying to add a scalar to my 'non-empty' missinglabelsinimage{1}.

I am not able to understand the error in my if condition. Any help would be appreciated.

Thanks in advance for your time

Best

Harish

[SreeHarish Muppirisetty]

I did the following checks:

(~isempty(missinglabelsinimage{1}))

ans =

     0
(~isempty(leftoverROI1s{1}))

ans =

     1
missinglabelsinimage{1}

ans =

   Empty matrix: 1-by-0

Answer 1

[Iain]

Before the if statement, add

 disp(~isempty(leftoverROI1s{1}))
 disp(~isempty(missinglabelsinimage{1}))

If both turn up with "1", you'll go into the loop. I suspect that missinglabelsinimage{1} contains a 1x1 cell array with an empty in it.

[SreeHarish Muppirisetty]

Hi,

I did the following checks:

(~isempty(missinglabelsinimage{1}))

ans =

     0
(~isempty(leftoverROI1s{1}))

ans =

     1
missinglabelsinimage{1}

ans =

   Empty matrix: 1-by-0