finding only unique values

3 vues (au cours des 30 derniers jours)
Bernard
Bernard le 22 Août 2013
Suppose you have a column vector, the values are integers(in order) but some of them are repeated, e.g. it could be [1,1,1,1,2,3,3,4,5,5,5,5,5] I want to find the indices of unique values e.g. the index of 2 and 4 in the aforementioned example. the unique function in matlab returns on top of truly unique the first value of any nonunique value, so it would return the index of the first 1, the first 3 and first 5 but I don't want those

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the cyclist
the cyclist le 22 Août 2013
Modifié(e) : the cyclist le 22 Août 2013
Maybe call these the "singleton" values. Here's one way:
x = [1,1,1,1,2,3,3,4,5,5,5,5,5];
unique_x = unique(x);
count_x = hist(x,unique_x);
singleton_x = unique_x(count_x==1)
  1 commentaire
Bernard
Bernard le 22 Août 2013
brilliant this saved me time thanks

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Plus de réponses (2)

David Sanchez
David Sanchez le 22 Août 2013
a=[1,1,1,1,2,3,3,4,5,5,5,5,5];
x = unique(a)
y = histc(a,x)==1;
lonely_values = find ( y == 1 )
or:
lonely_values = find ( (histc(a,unique(a))==1) == 1 )
lonely_values =
2 4

Azzi Abdelmalek
Azzi Abdelmalek le 22 Août 2013
[ii,jj]=sort(x);
out=sort(jj(strfind(logical([1 diff(ii) 1]),[true,true])))

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