How does one use integral2 (double integral) symbolically?
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Mikayel
le 22 Août 2013
Modifié(e) : Walter Roberson
le 14 Mai 2024
I would like to get some help on how to use the integral2 symbolically?
E.g. I have a Joint PDF function -> "@(x,y) exp(-(x+y))"
To verify that it adds up to one, I did the following -> "integral2(pdf,0,inf,0,inf)" with the result being 1 as expected.
Now to calculate the Joint CDF symbolically I defined x and y as symbols and tried to do -> "cdf=@(u,v) exp(-(u+v))" and "integral2(cdf,0,x,0,y)". The error I got was -> "Error using integral2. XMAX must be a floating point scalar."
What I want to get is -> "(1-exp(-y))*(1-exp(-x))" !!
Your help will be much appreciated.
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Dipak kumar Panigrahy
le 21 Mai 2020
clear
clc
syms rtstar
syms rt1 v delta R do %or assign numeric values to the variables
p=10;
cdf1=p*tan(delta)*R^2;
cdf2=p*tan(delta)*R^2;
eqn = ss == (int(int(cdf1,rt,rt1,rtstar),e,0,v)-int(int(cdf2,rt,rtstar,rt2),e,0,v));
sol = solve(eqn, rtstar)
can ayone tell me how to solve this eqn?
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Shashank Prasanna
le 22 Août 2013
From the documentation of integral2:
integral2
Numerically evaluate double integral
It is not meant for symbolic computation. If you are interested in symbolic results you need to have Symbolic Toolbox installed
Then you can use the int function:
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Shashank Prasanna
le 23 Août 2013
Modifié(e) : Shashank Prasanna
le 23 Août 2013
Sir, you have to use functions from the Symbolic Toolbox.
>> syms u v
>> cdf = exp(-(u+v))
>> int(int(cdf,v,0,v),u,0,u)
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Okae
le 14 Mai 2024
Modifié(e) : Walter Roberson
le 14 Mai 2024
how do i type j=\iint\of V_s\ [f\left(\varepsilon_{\left(\left(p+q\right)\right)}-f\left(\varepsilon_p\right)\delta\left(\varepsilon_{\left(\left(p+q\right)\right)}-\varepsilon_p-\hbar\omega q\right)\right]dp_{\left(x\right)d}p_y

in symbolic math toolbox?
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