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How can I integral this equation and plot? please help me

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jameslk
jameslk le 16 Juin 2021
Commenté : jameslk le 16 Juin 2021
dy/dt = y*t^2 + 3*y
y(0) = 1
t= 0:2
This is the equation which I want to integral
But when I integrate and plot this how can I get dy/dt. Because dy/dt becomes y when i intergrate it.
  2 commentaires
John D'Errico
John D'Errico le 16 Juin 2021
You want to plot the derivative?
Surely it would be true, that if you know y(t), and t, then you can compute dy/dt, since you have the expression right there.
jameslk
jameslk le 16 Juin 2021
yes i want to plot that equation after integral
and how can i get integral constant?
I don't have idea to do this with function int or integral

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Walter Roberson
Walter Roberson le 16 Juin 2021
syms y(t) c
eqn = diff(y) == y*t^2 + 3*y
eqn(t) = 
ic = y(0) == 1
ic = 
sol = dsolve([eqn, ic])
sol = 
fplot(sol, [0 2])

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