random number generation for known sum

3 vues (au cours des 30 derniers jours)
harley
harley le 27 Août 2013
Commenté : Tejas le 14 Juil 2020
i what do generate some 15 random numbers that sum for each separate value of say, 60 , 70, 40, 65. How would i go abouts this?
sum = [60 70 40 65];
n=15;
b = [ ];
for i = 1:1:n,
a = randi([1,??]);
b = [b a];
end

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Azzi Abdelmalek
Azzi Abdelmalek le 27 Août 2013
n=60;
m=1:n;
a=m(sort(randperm(60,15)));
b=diff(a);
b(end+1)=60-sum(b)
sum(b)
  13 commentaires
Bruno Luong
Bruno Luong le 13 Juil 2020
Modifié(e) : Bruno Luong le 13 Juil 2020
The easiest way is perhaps using Roger FEX function, then do some sort of "integering" the float solution
sumatarget = 60
n = 15;
ub = 7;
x = floor([0; cumsum(randfixedsum(n,1,sumatarget,0,ub))]);
x(end) = sumatarget; % prevent floating point error
r = diff(x)
The distribution might be not perfectly uniform but possibly close enough and suitable for what ever you want to do with it.
Tejas
Tejas le 14 Juil 2020
Integering the solution from Roger's function works very well for me. I do not require the numbers to be perfectly uniform. Thanks!

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Walter Roberson
Walter Roberson le 27 Août 2013

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