Loop to populate a 12 by 12 matrix

5 vues (au cours des 30 derniers jours)
DARLINGTON ETAJE
DARLINGTON ETAJE le 24 Juin 2021
Commenté : DARLINGTON ETAJE le 24 Juin 2021
Hello Guys,
I am tryling to form a 12 by 12 matrix for 11 elements. I am getting some errors. Take a look at my code below: it looks perfect to me but it is not working
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1=zeros(12,1);
K2=zeros(12,1);
K3=zeros(12,1);
K4=zeros(12,1);
K5=zeros(12,1);
K6=zeros(12,1);
K7=zeros(12,1);
K8=zeros(12,1);
K9=zeros(12,1);
K10=zeros(12,1);
K11=zeros(12,1);
K12=zeros(12,1);
K=zeros(12,12);
for i=1:n
K1(i)=[SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2(i)=[0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3(i)=[0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4(i)=[0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5(i)=[0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6(i)=[0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7(i)=-K1;
K8(i)=-K2;
K9(i)=-K3;
K10(i)=-K4;
K11(i)=[0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12(i)=[0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K(i)=[K1(i) K2(i) K3(i) K4(i) K5(i) K6(i) K7(i) K8(i) K9(i) K10(i) K11(i) K12(i)];
end
  1 commentaire
DARLINGTON ETAJE
DARLINGTON ETAJE le 24 Juin 2021
Thank you so much Walter. It worked. You are an excellent person. The only challenge is that working with the code in struct is different than in a double.

Connectez-vous pour commenter.

Réponse acceptée

Walter Roberson
Walter Roberson le 24 Juin 2021
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1 = repmat({zeros(12,1)},n,1);
K2 = repmat({zeros(12,1)},n,1);
K3 = repmat({zeros(12,1)},n,1);
K4 = repmat({zeros(12,1)},n,1);
K5 = repmat({zeros(12,1)},n,1);
K6 = repmat({zeros(12,1)},n,1);
K7 = repmat({zeros(12,1)},n,1);
K8 = repmat({zeros(12,1)},n,1);
K9 = repmat({zeros(12,1)},n,1);
K10 = repmat({zeros(12,1)},n,1);
K11 = repmat({zeros(12,1)},n,1);
K12 = repmat({zeros(12,1)},n,1);
K = repmat({zeros(12,1)},n,1);
for i=1:n
K1{i} = [SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2{i} = [0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3{i} = [0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4{i} = [0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5{i} = [0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6{i} = [0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7{i} = -K1{i};
K8{i} = -K2{i};
K9{i} = -K3{i};
K10{i} = -K4{i};
K11{i} = [0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12{i} = [0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K{i} = [K1(i); K2(i); K3(i); K4(i); K5(i); K6(i); K7(i); K8(i); K9(i); K10(i); K11(i); K12(i)];
end
K
K = 11×1 cell array
{12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell}
K{1}
ans = 12×1 cell array
{12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double}
K{1}{1}
ans = 12×1
0.3563 0 0 0 0 0 -0.3563 0 0 0

Plus de réponses (0)

Catégories

En savoir plus sur Structures dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by