How to subtract previous array element from the current one ?

10 vues (au cours des 30 derniers jours)
I have datastream as lines from the comport. All values are being parsed and I can choose the interested data. In this case, I want to subtract previous Easting value from the current one and calculate the distance between these two values each second when new string received. Could not create a 'for' loop for this operation;
s=serialport('COM14',115200);
configureTerminator(s,"CR/LF");
t = 0;
a = 0;
while true
t = t + 1;
line=readline(s);
ld=split(line,',');
Date=(ld{1});
UTC=(ld{2});
LAT=(str2double(ld{3}));
LONG=(str2double(ld{4}));
ALT=(str2double(ld{5}));
[Easting,Northing,UTMZone]=deg2utm(LAT,LONG);
HPOS=[Easting Northing];
SoG=(ld{6});
Depth=(ld{7});
CL=(ld{8});
AX=(str2double(ld{9}));
AY=(str2double(ld{10}));
AZ=(str2double(ld{11}));
GX=(str2double(ld{12}));
GY=(str2double(ld{13}));
GZ=(str2double(ld{14}));
MX=(str2double(ld{15}));
MY=(str2double(ld{16}));
MZ=(str2double(ld{17}));
Temp=(ld{18});
Bat=(ld{19});
ii=1:length(Date);
jj=2:length(Date);
test=zeros(length(HPOS),1);
for ix=1:length(Date)
test(ix)=HPOS(jj)-HPOS(ii);
end
end
when I run this code, I get the error message saying;
Index exceeds the number of array elements (2).
Error in Untitled5 (line 46)
test(ix)=HPOS(jj)-HPOS(ii);
Kind Regards,
Alper

Réponse acceptée

Scott MacKenzie
Scott MacKenzie le 25 Juin 2021
Modifié(e) : Scott MacKenzie le 25 Juin 2021
If you want to
subtract previous Easting value from the current one
see below. The value you want is EastingDiff.
EastingSave = 0;
while true
...
[Easting,Northing,UTMZone]=deg2utm(LAT,LONG);
EastingDiff = Easting - EastingSave;
EastingSave = Easting;
...
end
To avoid the error, get rid of the six lines beginning with ii = . You don't need them.
  1 commentaire
Mustafa Alper Cetintas
Mustafa Alper Cetintas le 25 Juin 2021
Modifié(e) : Mustafa Alper Cetintas le 25 Juin 2021
Appreciated ! That is what I was exactly looking for, thank you Sir.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Produits


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by