How to subtract previous array element from the current one ?
10 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Mustafa Alper Cetintas
le 25 Juin 2021
Modifié(e) : Mustafa Alper Cetintas
le 25 Juin 2021
I have datastream as lines from the comport. All values are being parsed and I can choose the interested data. In this case, I want to subtract previous Easting value from the current one and calculate the distance between these two values each second when new string received. Could not create a 'for' loop for this operation;
s=serialport('COM14',115200);
configureTerminator(s,"CR/LF");
t = 0;
a = 0;
while true
t = t + 1;
line=readline(s);
ld=split(line,',');
Date=(ld{1});
UTC=(ld{2});
LAT=(str2double(ld{3}));
LONG=(str2double(ld{4}));
ALT=(str2double(ld{5}));
[Easting,Northing,UTMZone]=deg2utm(LAT,LONG);
HPOS=[Easting Northing];
SoG=(ld{6});
Depth=(ld{7});
CL=(ld{8});
AX=(str2double(ld{9}));
AY=(str2double(ld{10}));
AZ=(str2double(ld{11}));
GX=(str2double(ld{12}));
GY=(str2double(ld{13}));
GZ=(str2double(ld{14}));
MX=(str2double(ld{15}));
MY=(str2double(ld{16}));
MZ=(str2double(ld{17}));
Temp=(ld{18});
Bat=(ld{19});
ii=1:length(Date);
jj=2:length(Date);
test=zeros(length(HPOS),1);
for ix=1:length(Date)
test(ix)=HPOS(jj)-HPOS(ii);
end
end
when I run this code, I get the error message saying;
Index exceeds the number of array elements (2).
Error in Untitled5 (line 46)
test(ix)=HPOS(jj)-HPOS(ii);
Kind Regards,
Alper
0 commentaires
Réponse acceptée
Scott MacKenzie
le 25 Juin 2021
Modifié(e) : Scott MacKenzie
le 25 Juin 2021
If you want to
subtract previous Easting value from the current one
see below. The value you want is EastingDiff.
EastingSave = 0;
while true
...
[Easting,Northing,UTMZone]=deg2utm(LAT,LONG);
EastingDiff = Easting - EastingSave;
EastingSave = Easting;
...
end
To avoid the error, get rid of the six lines beginning with ii = . You don't need them.
1 commentaire
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!