Access Matrix using array as keys

I have a matrix

    allPoints = ["10999970X10999700Y"    "11000310X12099960Y"    "10999970X12999700Y";
    "11999970X10999960Y"    "11999970X12000230Y"    "11999970X13000230Y";
    "12999970X10999700Y"    "12999970X12000230Y"    "12999970X13000230Y"]

And I want to select points based of rectangles, where I have bottom and top points of the rectangle

For a single rectangle with

bottom = [1 1]; top = [2 2];

I would use:

coveredPoints = allPoints(bottom(1):top(1),bottom(2):top(2))
%% OUTPUT
% coveredPoints = 
% 
%   2×2 string array
% 
%     "10999970X10999700Y"    "11000310X12099960Y"
%     "11999970X10999960Y"    "11999970X12000230Y"

which would return all the points from (1,1) to (2,2).

But now I have multiple bottoms and tops, and I want to get all the covered areas into a n x 1 array (single column array)

bottoms = [1 3; 2 2]; tops=[1 3; 2 2];
% When I try
coveredPoints = allPoints(bottoms(:,1):tops(:,1), bottoms(:,2):tops(:,2));
% It only returns the values for the first row only
% coveredPoints = 
%
%    "10999970X12999700Y"

Is there a way to extract all covered points onto a n x 1 array without a loop?

Answer 1

[Walter Roberson]

sub2ind()