Removing rows from a column depending on another column

1 vue (au cours des 30 derniers jours)
Christopher
Christopher le 8 Sep 2013
Hello,
I need a little bit of help with this problem. I will explain it the best I can then give a basic example below. Basically I have two column vectors. I am trying to split one of them up depending on the other. Basically I have:
Cp=[0;0.2;0.4;0.6;0.8;1;1.2;1.4];
Cf=[0;1;2;3;4;5;6;7;8];
I am trying to split up Cf depending on when Cp hits 1. So essentially, when Cp<=1 I am trying to obtain a column for Cf with only those values. So the resultant Cf would be:
Cf_new=[0;1;2;3;4;5]
So the only values obtained for Cf are when the corresponding row of Cp is less than or equal to 1. I hope this makes sense. Thank you

Réponse acceptée

Image Analyst
Image Analyst le 8 Sep 2013
Regarding your new question about extracting values of Cf only up to and including the index of the peak in Cp:
Cp=[0.2 0.4 0.8 0.99 0.8 0.4 0.2]
Cf=[0;1;2;3;4;5;6;7;8]
peakIndex = find(diff(Cp) < 0, 1, 'first')
Cf_new = Cf(1 : peakIndex)
In the command window:
Cp = 0.2 0.4 0.8 0.99 0.8 0.4 0.2
Cf =
0
1
2
3
4
5
6
7
8
peakIndex =
4
Cf_new =
0
1
2
3

Plus de réponses (2)

the cyclist
the cyclist le 8 Sep 2013
Cf_new = Cf(Cp<=1);
  4 commentaires
Christopher
Christopher le 8 Sep 2013
Yes, but the problem is all the values are less than 0.99, so it returns the entire original Cf column. Some how I need to obtain the number of rows from the beginning of Cf until it hits the peak.
Image Analyst
Image Analyst le 8 Sep 2013
That's a different question than you first asked. How are you defining "peak"? There is a findpeaks() function in the Signal Processing Toolbox. Or else you could just call diff(Cp) and look for the first negative value - it just depends on how you want to define a "Peak."

Connectez-vous pour commenter.


Andrei Bobrov
Andrei Bobrov le 8 Sep 2013
Modifié(e) : Andrei Bobrov le 8 Sep 2013
out = Cf(1:find(Cp>=.99,1,'first'));

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by