matrix problem not getting desired result.

A=[0 0 0 0 0;0 1 1 0 0;0 1 0 0 0;0 1 1 0 0]; [rows, cols] = find(A == 1); n1=min(cols); n2=max(cols); m1=min(rows); m2=max(rows); for i=n1:n2 count=0; for j=m1:m2 if A(j,i)==1 count=count+1; end end count1=count; end

RESULT: count1=2

REQUIRED RESULT: count1=[3 2]

Answer 1

[Geert]

Please try to format you question properly next time.

You want to know how many non-zero entries there are in each column I guess?

The easiest way of doing so is like this:

A=[0 0 0 0 0;0 1 1 0 0;0 1 0 0 0;0 1 1 0 0]; 
countPerColumn = sum(A==1,1);
% if you want to remove the zero entries you can add the following line:
countPerColumnRemovedZeros = countPerColumn;
countPerColumnRemovedZeros(countPerColumn == 0) = [];

If you want to adjust your own code (which is a bit sloppy in my opinion), you probably want something like this:

A=[0 0 0 0 0;0 1 1 0 0;0 1 0 0 0;0 1 1 0 0]; 
[rows, cols] = find(A == 1);
n1=min(cols); n2=max(cols); 
m1=min(rows); m2=max(rows); 

columns = n1:n2 ;
for ii=1:length(columns);
    count=0; 
    for j=m1:m2 
        if A(j,columns(ii))==1 
            count=count+1; 
        end
    end
    count1(ii)=count; 
end

[vaishali]

thank you very much...