the results of two functions talking to each other in a loop

Hello Everyone...so the code all the way to ghs is correct. I wanted you to see the background. However, I am having issues picking each matrix and using it in a function and getting results from one function to feed into another function in a loop.

function [bhs,ahs,cbs]=btime(t1,t2,t3)
    bhs=(t1*t2)+t3;
    ahs=t1+t3;
    cbs=t2./3;
end
function [abk,kba,t3]=ctime(bhs,cbs)
    abk=27.3.*bhs;
    kba=bhs+cbs;
    t3=35*(abk+kba);
end
    
wqe=[1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
kli=[51;52;53;54;55;56;57;58;59;60;61;62;63;64;65];
bbc=(21:1:35)';
hsd=size(kli,1);
kas=zeros(hsd,1);
sak=zeros(hsd,1);
cbb=zeros(hsd,1);
abc=zeros(hsd,3);
for i=1:hsd
    kas(i)=wqe(i);   
    sak(i)=kli(i);
    cbb(i)=bbc(i);
end
abc(1,:) = [kas(1) sak(1) cbb(1)];
for h=2:1:hsd    
    abc(h,:)=[kas(h) sak(h) cbb(h)];
end
matrix{1}=abc(1,:);
for i = 2:hsd
    matrix{i}=abc(1:i,:);
end
ghs=([]);
for iiv=1:1:hsd
    ghs(iiv)=(matrix{1,iiv}(:,:));
    t1=ghs(:,1);
    t2=ghs(:,2);    
    [bhs(iiv),ahs(iiv),cbs(iiv)]=btime(t1(iiv),t2(iiv),t3(iiv))
    [abk(iiv),kba(iiv),t3(iiv)]=ctime(bhs(iiv),cbs(iiv))
end
Final_Answer=[bhs cbs]; % The goal is to put each new bhs and cbs under the previous one.

[Joseph Cheng]

well if you debug the code the ghs(iiv) (single array index) is not able to fit the 1:3 array that is in matrix{1,1}(:,:) and for the next itration it gets larger and larger to 2x3, 3x3, etc. as matrix{i} = abs(1:index,:).... additionally in your ctim(bhs(iiv) cbs(iiv)) is missing the comma between bhs and cbs. oh and almost forgot you never defined t3. maybe these small corrections will get you a bit closer

[DARLINGTON ETAJE]

Joseph...thanks for your comments...refresh the page...I already put the comma before your message...also, T3 is defined. it it the output of the function ctime...the question is correct.

[Joseph Cheng]

must be missing something as your post still shows

for iiv=1:1:hsd
    ghs(iiv)=(matrix{1,iiv}(:,:));
    t1=ghs(:,1);
    t2=ghs(:,2);    
    [bhs(iiv) ahs(iiv) cbs(iiv)]=btime(t1(iiv),t2(iiv),t3(iiv))
    [abk(iiv) kba(iiv) t3(iiv)]=ctime(bhs(iiv) cbs(iiv))
end

which is missing the comma in ctime() as well as i point out that t3 which is not defined as its the output of ctime which is called AFTER you try to use t3. have you tried running your above code and debug the errors?

[DARLINGTON ETAJE]

Thanks. I have adjusted the code...my intention is to calculate T3 from one function and input it into the next function...help me out please

Answer 1

[Alan Moses]

Instead of using the ghs vector, you may use a temporary variable for the computation. The function 'btime' needs t3 variable to be defined before the function call. But the code only defines t1 and t2 before the function call and t3 is calculated in the next line when 'ctime' is called. The following code assumes you are using the third column of the matrix in the 'btime' function, but you have to change your algorithm if your intention is to reuse the T3 output of 'ctime' in 'btime'. Also, it is a good practice to preallocate the variables that change size on every loop.

T3 = zeros(1,hsd);
bhs = zeros(1,hsd);
ahs = zeros(1,hsd);
cbs = zeros(1,hsd);
abk = zeros(1,hsd);
kba = zeros(1,hsd);
for iiv=1:1:hsd
    temp=(matrix{1,iiv}(:,:));
    t1=temp(:,1);
    t2=temp(:,2);
    t3=temp(:,3);
    [bhs(iiv),ahs(iiv),cbs(iiv)]=btime(t1(iiv),t2(iiv),t3(iiv));
    [abk(iiv),kba(iiv),T3(iiv)]=ctime(bhs(iiv),cbs(iiv));
end

[DARLINGTON ETAJE]

Alan, thanks for the attempt. I am grateful.

see the final line of my code.

Final_Answer=[bhs cbs]; % The goal is to put each new bhs and cbs under the previous one.

You will realize that matrix contains several matrices with increasing sizes. so the eventual answer for bhs and cbs are meant to increase on every loop