how to calcuate mean with NaN

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Peihong
Peihong le 12 Sep 2013
Commenté : Esen S. le 21 Avr 2020
Dear Friend,
There are two matrixs with the same size, there are some NaNs in each matrix. I want to calculate the mean of corresponding datapoints, which might contain NaN. for example, A(1,2)=NaN, B(1,2)=3, I need the average of the sum of 3+NaN divided by the effective number of data points, here is 1 since A(1,2) is NaN, to be 3. If A(2,2)=2,B(2,2)=5, I need the average to be (2+5)divided by 2, which equals 3.5 since neither A(2,2) and B(2,2) contains NaN. Is there a way to achieve this goal without using a for loop? thanks

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Sven
Sven le 12 Sep 2013
Modifié(e) : Sven le 12 Sep 2013
If you have the Statistics Toolbox, just replace calls to mean() with calls to nanmean().
If you don't have it, you can do the same by downloading the File Exchange contribution nansuite
Here's an example:
A = reshape(1:4,2,2);
B = A + 10;
A([1 3]) = nan % Set some NaNs
B([1 2]) = nan
yourMean = nanmean(cat(3,A,B),3)
Which results in:
A =
NaN NaN
2 4
B =
NaN 13
NaN 14
yourMean =
NaN 13
2 9
  1 commentaire
Peihong
Peihong le 12 Sep 2013
Hi, Sven, thanks a lot. It's exactly what I need.

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Plus de réponses (2)

Jan
Jan le 12 Sep 2013
Emulating NANMEAN without the statistics toolbox is easy:
index = isnan(X);
X(index) = 0;
M = sum(X, 2) ./ sum(index, 2);
  1 commentaire
Esen S.
Esen S. le 21 Avr 2020
I belive there is a tilde missing in the last line.
It should be M = sum(X, 2) ./ sum(~index, 2);

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Shashank Prasanna
Shashank Prasanna le 12 Sep 2013

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