Effacer les filtres
Effacer les filtres

If all points are equal then

1 vue (au cours des 30 derniers jours)
Carolin Widmann
Carolin Widmann le 1 Juil 2021
Réponse apportée : Yazan le 1 Juil 2021
Hi everyone,
I have a cell with different arrays. The arrays contains different matrices (for example 72x2 double, 5x2 double, or 3x2double).
Now I want to have to if clauses. The first on is, that if the matrice is smaller then 5x2 a logical 0 results.
The same should happen when all entries of the first column of the matrice are equal to each other or when all entries of the second column are equal to each other.
How can I reach this?
for ii=1:length(xLoc)
for kk=1:length(area)
if length(points{kk}(:,1))<5 %5
elseif points{kk}(:,2)==%equal to each other
elseif points{kk}(:,1)==%equal to each other
edges = convhull(points{kk}(:,1),points{kk}(:,2));
in(kk) = inpolygon(xLoc(ii),yLoc(ii),points{kk}(edges,1),points{kk}(edges,2)); % true if VortexLoc is inside area
Thanks for your help!!

Réponses (1)

Yazan le 1 Juil 2021
% generate 3 matrices for a demo
A1 = randn(72,2);
A2 = randn(5,2);
A3 = randn(3, 2);
% generate a structure
s = {A1, A2, A3};
% 3 logical statement
f1 = cellfun(@(x) size(x,1)<5, s);
f2 = cellfun(@(x) all(x(:,1)==x(1,1)), s);
f3 = cellfun(@(x) all(x(:,2)==x(1,2)), s);
% or merge f1 and f2 and f3 in one logical statment
% f4 = f1 or f2 or f3
f4 = cellfun(@(x) size(x,1)<5 | all(x(:,1)==x(1,1)) | all(x(:,2)==x(1,2)), s);


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