Effacer les filtres
Effacer les filtres

An object with the biggest amount of scope in the Binary image

3 vues (au cours des 30 derniers jours)
Felix
Felix le 12 Sep 2013
Hello, I have a binary image with n white objects (not connected). How can I leave only the object with the biggest amount of scope in the picture I can do it by - bwareaopen, but in this way I have to know approximate size of an object. sorry for my english. thnx

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Image Analyst
Image Analyst le 13 Sep 2013
Try this:
grayImage = imread('coins.png');
subplot(2,2,1);
imshow(grayImage);
binaryImage = grayImage > 100;
binaryImage = imfill(binaryImage, 'holes'); % Fill holes.
[labeledImage, numObjects] = bwlabel(binaryImage);
stats = regionprops(labeledImage,'Area');
allAreas = [stats.Area]
[~, indexOfLargest] = max(allAreas);
largestBlob = ismember(labeledImage, indexOfLargest)>0;
subplot(2,2,2);
imshow(largestBlob);
title('Largest');
keeperIndexes = 1:numObjects;
keeperIndexes(indexOfLargest) = [];
binaryImage2 = ismember(labeledImage, keeperIndexes)>0;
subplot(2,2,3);
imshow(binaryImage2);
title('All Except Largest');

Plus de réponses (2)

Adam Filion
Adam Filion le 12 Sep 2013
Modifié(e) : Adam Filion le 12 Sep 2013
If you have Image Processing Toolbox you can use the function regionprops. It comes out to something like this, where tm is the binary image.
cc = bwconncomp(tm);
stats = regionprops(cc,'Area');
A = [stats.Area];
[~,biggest] = max(A);
tm(labelmatrix(cc)~=biggest) = 0;
You can watch a recorded presentation that steps through a similar example here:
  2 commentaires
Felix
Felix le 12 Sep 2013
Modifié(e) : Image Analyst le 13 Sep 2013
Thanks for the help, it close enough to what I asked, however, it erased all the small arias except the closest ones to the object . can you tall me why is that? sorry i can't upload an image, can i send it to your e-mail?
Image Analyst
Image Analyst le 13 Sep 2013
Modifié(e) : Image Analyst le 13 Sep 2013
Try uploading an image to http://snag.gy or http://tinypic.com.

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Sean de Wolski
Sean de Wolski le 17 Sep 2013
Good timing, I just posted this function a few minutes ago!

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