how can i do this summation

I have two summation ,a=0 to a=m+1 and b=0 to b=n+1,where m=100,n=50.?

8 commentaires

Azzi Abdelmalek
Azzi Abdelmalek le 18 Sep 2013
If m=2 and n=3 what should be the result?
Mary Jon
Mary Jon le 18 Sep 2013
Modifié(e) : Mary Jon le 18 Sep 2013
I am not need sum 3 with 2 to get 5 . I need summation from 0 to m+1,and from 0 to n+1,where n=50,m=100
Azzi Abdelmalek
Azzi Abdelmalek le 18 Sep 2013
Ok, show us the result for m=3 and n=2
Mary Jon
Mary Jon le 18 Sep 2013
my function is M=sum(a=0 to a=m+1)sum (b=0 to b=n+1)(abs(fun(m)-fun(n)) I don't know result for m=3 and n=2
Azzi Abdelmalek
Azzi Abdelmalek le 18 Sep 2013
This is not clear
Mary Jon
Mary Jon le 18 Sep 2013
Modifié(e) : Azzi Abdelmalek le 18 Sep 2013
MPD=(∑_(a=0, n+1)∑_(b=0,m+1)|(v_(i,j)^(k+1)-(v_(i,j))^(k) |))/((m.n))
Azzi Abdelmalek
Azzi Abdelmalek le 18 Sep 2013
a and b are not used in your sum. What are i and j? what is k?
Mary Jon
Mary Jon le 18 Sep 2013
Modifié(e) : Azzi Abdelmalek le 18 Sep 2013
sorry sorry
MPD=(∑_(a=0, n+1)∑_(b=0,m+1)|(v_(a,b)^(k+1)-(v_(a,b))^(k) |))/((m.n))
k=1:88(as ex)
how do it (writing)

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 Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 18 Sep 2013
Modifié(e) : Azzi Abdelmalek le 18 Sep 2013

1 vote

s=zeros(1,88);
for k=1:88
for a=0:n+1
for b=0:m+1
s(k)=s(k)+v(a+1,b+1)^(k+1)-v(a+1,b+1)^k
end
end
end
s=s/(m*n)

Plus de réponses (2)

Walter Roberson
Walter Roberson le 18 Sep 2013

0 votes

Supposing that f(a,b) gives you the term you are summing, then
[A, B] = ndgrid(0:m+1, 0:n+1);
fAB = arrayfun(@f, A, B);
sum(fAB(:))
or
fAB = bsxfun(@f, (0:m+1).', 0:n+1);
sum(fAB(:))

3 commentaires

Mary Jon
Mary Jon le 18 Sep 2013
matlab error
??? Undefined command/function 'arrayfun'. ??? Undefined command/function 'bsxfun'.
I am using matlab 7
Walter Roberson
Walter Roberson le 18 Sep 2013
MATLAB 7... you mean R14? Is it at least R14SP1 ?
Mary Jon
Mary Jon le 20 Sep 2013
yes,I mean R14

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