How to divide a signal to a function?

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Fatemeh Sharafi
Fatemeh Sharafi le 13 Juil 2021
Commenté : Fatemeh Sharafi le 13 Juil 2021
Hi dear friends. I have a nonstationary signal and I want to divide it to a 4-order polynomial function. but the result doesn't seem correct:
I simply do it like :
w= signal./function
Here's the signal plot:
this is the function:
and the result (when I divide them) is this:
I don't know what that big peak is? Logcally it shouldn't seem like this and should be like a stationary signal
I would be so garteful if you guide me

Réponse acceptée

Chunru
Chunru le 13 Juil 2021
The "function" has a value close to 0 and thus division by 0 (or small value) results in the big peak.
  3 commentaires
Chunru
Chunru le 13 Juil 2021
It depends on what you want to do, which you did not explain clearly. Anyway you should always avoid the division by zero. You many consider the following:
w= signal./ (f+0.5); % don't use function as variable name
Fatemeh Sharafi
Fatemeh Sharafi le 13 Juil 2021
this function was obtained from curve fitting the 4th-order polynomial func to a non-statinary signal. Then I used the fit function to convert the nonstationary signal to stationary by divide them.
thanks by the way. Your help was perfect

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