How to compute poles-zeros using matlab?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
H(z)=(1-2^-2)/(1-0.9*z^-1+0.6*z^-2+0.5*z^-3)
b=[1 0 -1 0];
a=[1 0.9 0.6 0.5];
% to find zeors
zeros=roots(b)
% to find poles
poles=roots(a)
% to plot
zplane(b,a)
Is my approach correct?
0 commentaires
Réponses (1)
Mathieu NOE
le 19 Juil 2021
hello
I hope the coefficient in b and a are correct (then the zeros and poles are inside the unit circle ) , because the first line is not 100% matching the coefficients you declared in b and a :
H(z)=(1-2^-2)/(1-0.9*z^-1+0.6*z^-2+0.5*z^-3) should be then replaced by :
H(z)=(1-z^-2)/(1+0.9*z^-1+0.6*z^-2+0.5*z^-3)
otherwise the zeros and pole computation is correct , and there is also this method (FYI) :
% alternative :
[Z,P,K] = tf2zp(b,a)
0 commentaires
Voir également
Catégories
En savoir plus sur Digital Filter Analysis dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!