In the following script, shifting the % symbols to the line below where they are shown givies different results. The version shown below gives the correct result. The versison with the % signs moved gives an incorrect result. Any ideas?
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% trajetory 1
clf
xx=1:10;y=[1 0 0 0 0 0 0 0 1 0];stem(xx,y)
hold on
m = .1;
xz(1) = 11;
y(1) = 1.1;
for i = 1:10
%xz(i) = xz(1) - i;
xz(i) = 11 - i;
%y(i) = y(1) - m*xz(i);
y(i) = 1.1 - m*xz(i);
end
plot(xz,y)
1 commentaire
Image Analyst
le 27 Sep 2013
Again? A third post on the same question? This tells me that a reply to Fred is a complete waste of time.
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Walter Roberson
le 27 Sep 2013
The commented out code modifies xz(1) when "i" is 1, so when "i" is 2 or more, xz(1) is no longer the same as what it started out as.
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