In the following script, shifting the % symbols to the line below where they are shown givies different results. The version shown below gives the correct result. The versison with the % signs moved gives an incorrect result. Any ideas?

% trajetory 1

clf

 xx=1:10;y=[1 0 0 0 0 0 0 0 1 0];stem(xx,y)
 hold on

 m = .1; 
 xz(1) = 11;  
 y(1) = 1.1; 

 for i = 1:10

         %xz(i) = xz(1) - i;
         xz(i) = 11 - i;
         %y(i) = y(1) - m*xz(i);
         y(i) = 1.1 - m*xz(i);
 end

 plot(xz,y)

[Image Analyst]

Again? A third post on the same question? This tells me that a reply to Fred is a complete waste of time.

Answer 1

[Walter Roberson]

The commented out code modifies xz(1) when "i" is 1, so when "i" is 2 or more, xz(1) is no longer the same as what it started out as.