I want to shorten a string.

I have this string that contains information about the date and the hour of the acquistion.

Start=2021-06-11T:12:32:04:122

The result I am looking for is this:

12:32:04:122

Answer 1

[Walter Roberson]

If it is a string() object then see extractAfter()

Answer 2

[DGM]

You can use regexp() on either strings or chars.

timestamp = 'Start=2021-06-11T:12:32:04:122';
out = regexp(timestamp,'(?<=:).*','match')

out = 1×1 cell array
    {'12:32:04:122'}

Given that you probably have more than one timestamp to process, you may have to tweak things depending on whether you're dealing with a string array or a cell array of char vectors. In this case, the input is a char vector and the output is a cell array of char vectors. Consider the case where the input is a cell array of char vectors:

timestamp = 'Start=2021-06-11T:12:32:04:122';
timestamp = {timestamp; timestamp; timestamp};

out = regexp(timestamp,'(?<=:).*','match');
out = vertcat(out{:})

out = 3×1 cell array
    {'12:32:04:122'}
    {'12:32:04:122'}
    {'12:32:04:122'}