Adding layers to narxnet

Hello everybody, I am currently running into trouble when I try to modify the narxnet example given in the documentation (ph Neutralization process)

While I was able to change activation functions, I#ve run into trouble when adding an additional layer.

The current code:

trainFcn = 'trainlm';
inputDelays = 1:10;
feedbackDelays = 1:10;
hiddenLayerSize = 10;
net = narxnet(inputDelays,feedbackDelays,hiddenLayerSize,'none',trainFcn);


net.inputConnect = [1 1; 0 0];

net.inputs{1}.processFcns = {'removeconstantrows','mapminmax'};
net.inputs{2}.processFcns = {'removeconstantrows','mapminmax'};

[x,xi,ai,t] = preparets(net,X,{},T); 

net.divideFcn = 'dividerand';  % Divide data randomly
net.divideMode = 'time';  % Divide up every sample
net.divideParam.trainRatio = 70/100;
net.divideParam.valRatio = 15/100;
net.divideParam.testRatio = 15/100;

net.numlayers = 3; %Add a layer, this sadly also adds more outputs..

net.layers{2}.transferFcn = 'purelin';
net.layers{2}.size = 1;
net.layers{3}.size = 1;
net.layers{3}.transferFcn = 'purelin'; %Double purelin is pointless, but I am just doing this for testing purposes.

net.inputConnect = [1 1; 0 0; 0 0];
net.layerConnect = [0 0 0; 1 0 0; 0 1 0];
net.biasConnect = [1; 1; 1];
net.outputConnect = [0 0 1];

%noloop(net)

net.outputs{3}.feedbackInput = 2; %The third output is addded prior to this by increasing the layer amount.
net.outputs{3}.feedbackMode = 'open';

net.performFcn = 'mse';

net.plotFcns = {'plotperform','plottrainstate', 'ploterrhist', ...
    'plotregression', 'plotresponse', 'ploterrcorr', 'plotinerrcorr'};

This sadly adds another output (the real output because net.outputs{1} and net.outputs{2} are just empty.

I think the problem arises from this: net.inputs{2}.feedbackOutput = 2.

But that field is read-only and can't be changed. This creates the unwanted network as seen in the image above. I basically want the ouput to loop to y(t) instead (and have only the two input vectors of course instead of 3 inputs).

If there is anybody with an idea I would be quite happy for help.