Solving Matrix Index Problem

is anyone here know how to solve matrix index problem in matlab?? For example the following problem :

You have a matrix for which each row is a person and the column represent the number of quarters, nickels, dimes, and pennies. What is the raw index of the person with the most money?

Note for those unfamiliar with American coins ; quarter = $ 0.25, dime = $ 0.10, nickel = $ 0.05, penny = $0.01

Example :

Input a = [1 0 0 0 ; 0 1 0 0] output b = 1

since the first person will have $ 0.25 and the second person will have only $0.05

Thanks you, i need the answer..

Answer 1

[Azzi Abdelmalek]

c=[0.25 0.1 0.05 0.01]
a = [1 0 0 0 ; 0 1 0 0]
[max_money,b]=max(sum(bsxfun(@times,c,a),2))

[Zaki]

Thanks for your help

Answer 2

[Rahul Sharma]

clear all
clc
a=randi(4,3,4)
k=[0.25 0.10 0.05 0.01];
for j=1:4
    for i=1:3
        a(i,j)=k(j)*a(i,j)
    end
end
b=max(sum(a'))
disp(b)

Answer 3

[Rahul Sharma]

a=randi(4,3,4)
a(:,1)=0.25*a(:,1);
  a(:,2)=0.10*a(:,2);
  a(:,3)=0.05*a(:,3);
  a(:,4)=0.01*a(:,4);
  disp(a)
  b = max(sum(a'));
  disp(b)

Answer 4

[Mohana Segaran]

a = [1 0 0 0; 0 1 0 0; 1 1 1 0];

b = [0.25 0.1 0.05 0.01; 0.25 0.1 0.05 0.01; 0.25 0.1 0.05 0.01];

x = dot(a,b,2);

[y z]= max(x);

z

Answer 5

[Stephen23]

The simple and efficient approach is to use MTIMES:

M = [1,0,0,0;0,1,0,0;0,2,1,1] % any number of rows

M = 3×4

1 0 0 0 0 1 0 0 0 2 1 1

V = [0.25;0.1;0.05;0.01]; % one column
[~,X] = max(M*V)

X = 3