generating random values within a range with condition

i can see this works but which part of my script can i make use of the function "while" so that i dont have to repeat this script again for row 2 to row 7?

or can anyone advise me a more efficient way perform the task? Thank you in advance,your advice would be greatly appreciated.

[Azzi Abdelmalek]

Posting a code as an image is not useful, we can not test it

[Roger Stafford]

The "rejection" method you are using has a serious flaw in the cases where the user happens to select a value very close to 3. For example, if 2.95 is chosen, the odds that a row of your randomly selected 'p' would satisfy your condition is one in about fifty billion - to be precise, one in 10^7*factorial(7). That would require a great many rejections on the average before succeeding.

Answer 1

[Image Analyst]

You could do this:

clc;
x = 19; % For example.
% Get sample data.
p = 2.5 + 0.5 * rand(7,7)
% Sum up the rows, going across columns within each row.
sumsOfRows = sum(p, 2)
% Find which rows don't sum up to x or greater.
badRows = find(sumsOfRows < x)
% While loop to replace the bad rows.
while any(badRows)
  for row = 1 : length(badRows)
    % For each bad row, replace just that row with another try.
    p(badRows(row),:) = 2.5 + 0.5 * rand(1,7)
  end
  % Check again.
  sumsOfRows = sum(p, 2)
  badRows = find(sumsOfRows < x)
end

By the way, you seem to be getting confused if the sum is to be called A or X, and whether A or X is an integer or a floating point number. Very sloppy & careless problem statement. But now you can't ethically turn it in, so you'll have to come up with your own variant using a while statement. There are other ways to do it though.

[Austin]

This suggestion works! Thanks LOTS!!