Speed up a for loop in my programme?

1 vue (au cours des 30 derniers jours)
Alberto Paniate
Alberto Paniate le 29 Juil 2021
Hi, one of the part of my programme contains this piece of code:
size2=2500;
gran=3;
A=ones(size2,size2);
for k=1:gran:(size2-gran)
for j=1:gran:(size2-gran)
X=rand*2*pi-pi;
for h=1:gran
for l=1:gran
A(k+l-1,j+h-1) = A(k+l-1,j+h-1) *exp(+1i*X); %phase in the square gran x gran
end
end
end
end
My pc runs this code in 0.60 seconds but I would like to know if it is possible to speed up this process.
I have already looked similar questions like:
but I don't know if I can apply to my problem
  2 commentaires
Yongjian Feng
Yongjian Feng le 29 Juil 2021
Can this be written as matrix operations? If so, then use the corresponding matlab matrix operation. Then Matlab might be able to optimize the process for you.
Alberto Paniate
Alberto Paniate le 29 Juil 2021
I don't know, I have to create a matrix X of random numbers each square of sides gran x gran. In these squares the randoms numbers are equal

Connectez-vous pour commenter.

Réponses (1)

Eike Blechschmidt
Eike Blechschmidt le 30 Juil 2021
If I understood you right this could do the trick and is about 2.5x faster on my machine.
tic();
X=rand(size2*size2,1)*2*pi-pi;
[row,col] = ind2sub([size2, size2],1:size2*size2);
blockRow = ceil(row/gran);
blockCol = ceil(col/gran);
idx = sub2ind([size2/gran, size2/gran], blockRow, blockCol);
A = ones(size2, size2);
A(1:size2*size2) = exp(+1i*X(idx));
toc();
Important to not is that size2 needs to be a multiple of gran to for this solution to work.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by