Can one get fitted value without going to predict?
1 view (last 30 days)
Jeff Miller on 30 Jul 2021
From your reference to 'predict', I'm guessing you have a vector of observed x values and you want to compute the predicted y for those x's. If so, then you want something like this:
xwithintercept = [1 x]; % maybe x' depending on row vs column vector
predictedY = sum( xwithintercept .* mdl.Coeffificent.Estimate)