Using cell array for indexing
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have matrices of varying dimensionality I need to index.
So just writing A(i1,...,in) is not an option because n can vary in my application.
What is known to work for getting a single element out of A is using a cell array:
IndArray={i1,...,in}
Elem=A(IndArray{:})
However I'd like to do something like SubMatrix= A(i1,i2,...,im,:,:,...,:), where m<n. Is there a way to do that?
The following does not work:
IndArray={i1,...,im}
SubMatrix=A(IndArray{:})
Thanks in advance for any hints.
0 commentaires
Réponse acceptée
Rik
le 2 Août 2021
I would suggest something like this:
IndArray={i1,...,im}
for dim=(numel(IndArray)+1):ndims(A)
IndArray{dim}=1:size(A,dim);
end
SubMatrix=A(IndArray{:})
0 commentaires
Plus de réponses (2)
Stephen23
le 2 Août 2021
Modifié(e) : Stephen23
le 2 Août 2021
No need for a loop, here is the simple and efficient MATLAB approach:
IndArray = {i1,..,im};
IndArray(1+end:ndims(A)) = {':'};
SubMatrix = A(IndArray{:})
How it works: MATLAB always allows a scalar element on the RHS to be allocated to any number of elements on the LHS. This applies to any array class: numeric, cell (as above), char, string, struct, etc.
Lionel Pöffel
le 2 Août 2021
1 commentaire
DGM
le 2 Août 2021
Sorry about that. I tried reading your other posts to try to figure out what exactly you were trying to do and had the feeling that I had misunderstood the intent.
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!