Error in plotting function of atand against different values of angle

1 vue (au cours des 30 derniers jours)
Muhammad Rehan
Muhammad Rehan le 7 Oct 2013
Hi All, I am getting error Error using atand Argument should be real while executing below code. Kindly help to correct it.
n1=1.51;
n2=1;
anglec = asind (n2/n1);
angleTE=[];
angleTM=[];
for angle= 1:20:90
angleTE(angle)= 2*atand((sqrt (((sind (angle))^2) - ((sind (anglec))^2))) / (cosd (angle)));
angleTM(angle) = 2*atand( (sqrt (((sind(angle))^2) - ((sind (anglec))^2))) / ((cosd (angle))*(sind(anglec))^2));
end
plot(angle,angleTE)
plot(angle,angleTM)

Réponses (1)

Walter Roberson
Walter Roberson le 7 Oct 2013
When angle < anglec then sind(angle)^2 < sind(anglec)^2 so subtracting the two gives a negative and sqrt() of a negative is imaginary.
Side note: as both expressions have (sqrt (((sind (angle))^2) - ((sind (anglec))^2))) in the numerator, calculate that once per loop iteration and then the two angle calculations simplify.
You should be considering whether you should use atan2() and then converting the radian answer to degrees.
  5 commentaires
Walter Roberson
Walter Roberson le 8 Oct 2013
Is there perhaps something in the phrasing of the question to indicate that theta1 must be greater than thetac ? Because the expression in the sqrt() can definitely end up negative.
Muhammad Rehan
Muhammad Rehan le 8 Oct 2013
Modifié(e) : Muhammad Rehan le 8 Oct 2013
yes you are right i have modified the code but now getting error in plot command.
Error using plot Vectors must be the same lengths.
n1=1.51;
n2=1;
anglec = asind (n2/n1);
angle= 42:1:90;
for ii = 42:1:90
angleTE(ii)= 2*atand((sqrt (((sind (ii))^2) - ((sind (anglec))^2))) / (cosd (ii)));
angleTM(ii) = 2*atand( (sqrt (((sind(ii))^2) - ((sind (anglec))^2))) / ((cosd (ii))*(sind(anglec))^2));
end
plot(angle,angleTE)

Connectez-vous pour commenter.

Catégories

En savoir plus sur Startup and Shutdown dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by