Operator '+' is not supported for operands of type 'matlab.gr​aphics.pri​mitive.Ima​ge'

I try to append image from tvec_json to 'tvec' array but I face this problem. Please anyone help. Here is my code below:

input_name = "output_wp2camera.json";
raw = fileread(input_name); 
input_params = jsondecode(raw);

camera_matrix = input_params.camera_matrix;
dist = input_params.dist_coefs;
tvec_json = input_params.translational_vectors;
rvec_json = input_params.rotational_vectors;

tvec  = [];
rvec = [];
len = length(tvec_json);
for i = 1:len
    tvec.append(array(tvec_json(image + string(i))))
    rvec.append(array(rvec_json(image + string(i))))
end

Answer 1

[Walter Roberson]

You did not assign a value to a variable named image, so image is being found as a function. Your line

tvec.append(array(tvec_json(image + string(i))))

is equivalent to

tvec.append(array(tvec_json(image() + string(i))))

We recommend that you avoid using image as the name of a variable to prevent running into this kind of problem.

[Md Shahidul Islam]

Thank you for your response. But it (tvec.append(array(tvec_json(image() + string(i))))) doesn't work. I need image because I decleared it as image. Here is my json code:

"translational_vectors":{

"image0":[

[

-49.99044630774815

],

[

-39.7190405880838

],

[

167.95558251589298

]

],

}

[Image Analyst]

Again, DO NOT use image as the name of your variable. Call it myImage or inputImage or anything else other than image because image is a build-in function. Then you will need to define myImage as something before you use it.

[Walter Roberson]

It appears that image is intended to be a constant there, rather than a variable name.

tvec.append(array(tvec_json("image" + string(i))))

[Md Shahidul Islam]

Thank you so much for your support and suggestion