How can I turn s/s to 1?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I run this code and if I click yes without change anything in the inputdlg, I receive 's/s'. How can I return this to '1' in this situation?
prompt={'Proportional Coefficient Input','Integral Coefficient Input','Derivative Coefficient Input'};
defans={'1','0','0'};
answer=inputdlg(prompt,'PID Coefficient Input',1,defans,'on');
if (~isempty(answer))
if (~isempty(answer{1}))&(~isempty(answer{2}))&(~isempty(answer{3}))&(answer{1}~='0')
syms s
x1=str2num(answer{1});
x2=str2num(answer{2});
x3=str2num(answer{3});
handles.pid(1)=x1(1);
handles.pid(2)=x2(1);
handles.pid(3)=x3(1);
handles.PID_num=[handles.pid(3),handles.pid(1),handles.pid(2)];
handles.PID_den=[1,0];
handles.PID_sys=tf(handles.PID_num,handles.PID_den);
evalc('handles.PID_sys')
end
end
0 commentaires
Réponse acceptée
Paulo Silva
le 8 Juin 2011
prompt={'Proportional Coefficient Input','Integral Coefficient Input','Derivative Coefficient Input'};
defans={'1','0','0'};
answer=inputdlg(prompt,'PID Coefficient Input',1,defans,'on');
if (~isempty(answer))
if (~isempty(answer{1}))&(~isempty(answer{2}))&(~isempty(answer{3}))&(answer{1}~='0')
syms s
x1=str2num(answer{1});
x2=str2num(answer{2});
x3=str2num(answer{3});
handles.pid(1)=x1(1);
handles.pid(2)=x2(1);
handles.pid(3)=x3(1);
handles.PID_num=[handles.pid(3),handles.pid(1),handles.pid(2)];
handles.PID_den=[1,0];
handles.PID_sys=tf(handles.PID_num,handles.PID_den);
[num,den] = tfdata(handles.PID_sys);
if(num{:}==den{:})
handles.PID_sys=1;
end
evalc('handles.PID_sys')
end
end
7 commentaires
Plus de réponses (1)
Walter Roberson
le 8 Juin 2011
s/s is not generally 1. In particular, that fails for 0, infinity, -infinity, and NaN.
1 commentaire
Paulo Silva
le 8 Juin 2011
that's why the tf leaves the results the way it does, I never seen the s/s situation before, always had transfer functions with more poles than zeros, sometimes it's good to be here trying to help others, we always learn new things.
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!