what's the error in nonlinear solution code?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
In false position method
-
fx=inline('exp(-2*x)-0.5')
a=input('a=');<<0
b=input('b=');<<1
fa=fx(a);
fb=fx(b);
if fa*fb>0.0
fprintf('not value in rangement');
return
elseif fa==0.0
fprintf('a is true value');
return
elseif fb==0.0
fprintf('b is true value');
return
end
epsilon=0.0001;
imax=1000;
for iter=1:imax
xc=b-fb*(a-b)/(fa-fb);
fc=fx(xc);
fprintf('\n xc f(xc) : %f , %f', 'xc', 'fc');
if abs(fc) <= epsilon
fprintf('\n value xc= %f','xc');
return
end
test = fa*fc;
if test <0.0
b=xc;
fb=fc;
elseif test > 0.0
a=xc;
fa=fc;
end
end
xc f(xc) : 120.000000 , 99.000000
xc f(xc) : 102.000000 , 99.000000
xc f(xc) : 120.000000 , 99.000000
xc f(xc) : 102.000000 , 99.000000
value xc= 120.000000
value xc= 99.000000>>
i don't understand why the result show '120' repeatedly. which means what??
thanks for you help
0 commentaires
Réponses (0)
Voir également
Catégories
En savoir plus sur Guidance, Navigation, and Control (GNC) dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!