Given a vector of assorted positive integers, how to create a vector with the means of every 2 integers inserted between each other?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I've managed to take the mean of the whole vector with the mean function, but this doesn't seem like the right path to take. I am thinking of: v= 2 6 8 3 1 9 4 5 7 m1= v(1,2:9) m2= [m1,v(end)] m3= [v;m2] vmeans=mean(m2)
there are quite a few intermediate steps just to get to the vector of the means by themselves.
any answers to get to these values better or how to insert those values in between each original integer are much appreciated
thanx
0 commentaires
Réponse acceptée
David Young
le 9 Juin 2011
result = interp1(v, linspace(1, length(v), length(v)*2-1), 'linear')
2 commentaires
David Young
le 12 Juin 2011
Yes, to understand this it may help to note that, for example
linspace(1, 3, 5)
gives
[1 1.5 2 2.5 3]
- that is, the points in the index space of v for which you want to find values.
Plus de réponses (3)
David Young
le 9 Juin 2011
result(1:2:2*length(v)-1) = v;
result(2:2:2*(length(v)-1)) = conv(v, [1 1]/2, 'valid')
0 commentaires
Andrei Bobrov
le 9 Juin 2011
m2 = v([2:end,end]);
m3 = [v;m2];
vmeans = mean(m2);
EDIT
vout = reshape([v;conv(v,[1 1],'valid')/2 0],1,[]);
vout = vout(1:end-1);
more only it case
vout = interp1(1:length(v),v,1:.5:length(v));
4 commentaires
David Young
le 9 Juin 2011
It's more efficient to divide the mask in the convolution by 2, rather than dividing the result of the convolution by 2.
linspace is preferable to using the colon operator if the output needs to be a definite length and the increment is not an integer.
David Young
le 9 Juin 2011
v= [2 6 8 3 1 9 4 5 7]; % data
m = (v(1:end-1)+v(2:end))/2;
t = [v; [m 0]];
t = t(:);
result = t(1:end-1).'
0 commentaires
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!